4y^3-10y^2/2y^2

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Solution for 4y^3-10y^2/2y^2 equation: 


y in (-oo:+oo)

4*y^3-(((10*y^2)/2)*y^2) = 0

4*y^3-5*y^4 = 0

4*y^3-5*y^4 = 0

y^3*(4-5*y) = 0

4-5*y = 0 // - 4

-5*y = -4 // : -5

y = -4/(-5)

y = 4/5

y^3 = 0

1*y^3 = 0 // : 1

y^3 = 0

y = 0

y in { 4/5, 0 }

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